Asked by amber
                if Y varies jointly as X and the square of Z, and if Y=24 when X=2 and Z=6, find Y when X=10 and Z=9
            
            
        Answers
                    Answered by
            Reiny
            
    y = kxz^2 , where k is a constan
given: y = 24, x=2, z=6
24 = k(2)(36)
k = 24/72 = 1/3
y = (1/3)xz^2
when x=10,z=9
y = (1/3)(10)(81) = 10/243
    
given: y = 24, x=2, z=6
24 = k(2)(36)
k = 24/72 = 1/3
y = (1/3)xz^2
when x=10,z=9
y = (1/3)(10)(81) = 10/243
                    Answer
            
    y varies jointly with z and the square of x. y=16 when z =2 and x=3, find y when z=3 and x=4
    
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