Question

A ship leaves port at 6 am travelling due east at 12mph. Another ship leaves port at 11 am travelling due north at 15 mph. How far apart, to the nearest tenth of a mile are the 2 ships at 11 pm?
by 11 pm, ship1 has gone 17*12 = 204 miles east
Also, ship2 has gone 180 miles north

the final separation is thus

d^2 = 204^2 + 180^2
d = 272.1 miles

Related Questions

A ship leaves port and heads due east at a rate of 32 miles per hour. Ever since the ship left por... a ship leaves a port at 6 am traveling due east at 12mph. another ship leaves a port 11 am traveling... We know this is a piecewise function and we solved the first part, but we cannot figure out the othe... A ship leaves port at noon at heads due east at 20 nautical miles/hour (20 knots). At 2PM the ship c...