Asked by Alexandra
A 16.0-N weight slides down a rough inclined plane that makes an angle of 28.0° with the horizontal. The weight, which started from rest, gains a speed of 15.0 m/s after sliding 150 m. How much work is done against friction?
Answers
Answered by
charrice
use the work-energy theorem
determine mass = 16.0N/9.8 m/s^2
initial velocity = 0; so initial KE = 0
final velocity = 15.0 m/s
final height = 0; so final PE = 0
initial height = 150 sin 28.0 degrees
substitute values in the work-energy theorem expression
determine mass = 16.0N/9.8 m/s^2
initial velocity = 0; so initial KE = 0
final velocity = 15.0 m/s
final height = 0; so final PE = 0
initial height = 150 sin 28.0 degrees
substitute values in the work-energy theorem expression
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