Asked by dee

A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of the incline, in degrees, is most nearly:

Answered by bobpursley
well, constant velocity, so weight going down = friction force
mg*sinTheta=mu*mgcosTheta
tantheta=mu
Answered by KHL
[ ì k = tan èk ]
Answered by john
45