Asked by dee
                A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of the incline, in degrees, is most nearly:
            
            
        Answers
                    Answered by
            bobpursley
            
    well, constant velocity, so weight going down = friction force
mg*sinTheta=mu*mgcosTheta
tantheta=mu
    
mg*sinTheta=mu*mgcosTheta
tantheta=mu
                    Answered by
            KHL
            
    [ ì k = tan èk ]
    
                    Answered by
            john
            
    45
    
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