Asked by casey
a 35.5kg box slides down an incline plane with a 25 degree angle at a constant rate. how do i calculate the coefficient of friction
Answers
Answered by
Henry
35.5kg * 9.8 = 347.9N @ 25deg.
Fp = 347.9*sin25 = 147N acting downward
parallel to plane.
Fv = 347.9*cos25 = 315.3N acting downward perpendicular to plane.
Fp - u*Fv = ma,
a = 0 (constant speed),
Therefore, Fp - u*Fv = 0,
u*Fv = Fp = 147,
315.3u = 147,
u = 147 / 315.3 = 0.47 = coefficient of friction.
Fp = 347.9*sin25 = 147N acting downward
parallel to plane.
Fv = 347.9*cos25 = 315.3N acting downward perpendicular to plane.
Fp - u*Fv = ma,
a = 0 (constant speed),
Therefore, Fp - u*Fv = 0,
u*Fv = Fp = 147,
315.3u = 147,
u = 147 / 315.3 = 0.47 = coefficient of friction.
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