Asked by math help 3
the center of circle x^2 + y^2 + 6y + 1 = 0 is??
Answers
Answered by
bobpursley
make the y^2+6y+1 a perfect square
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3