Asked by math help 3
                the center of circle x^2 + y^2 + 6y + 1 = 0 is?? 
            
            
        Answers
                    Answered by
            bobpursley
            
    make the y^2+6y+1 a perfect square
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3
    
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3
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