Asked by math help 3

the center of circle x^2 + y^2 + 6y + 1 = 0 is??

Answers

Answered by bobpursley
make the y^2+6y+1 a perfect square

y^2+6y+9

by adding 8 to each side.

x^2+(y+3)^2=8

center: 0,-3
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