Asked by math help 3
the center of circle x^2 + y^2 + 6y + 1 = 0 is??
Answers
Answered by
bobpursley
make the y^2+6y+1 a perfect square
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3
y^2+6y+9
by adding 8 to each side.
x^2+(y+3)^2=8
center: 0,-3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.