Asked by J.R.
The center of a circle is A(-3,3) an B(1,6) is in the circle. Find the area of the circle in terms of pi.
a^2 + b^2 = c^2 radius is 5 and 25pi
a^2 + b^2 = c^2 radius is 5 and 25pi
Answers
Answered by
Reiny
You must mean that
b(1,6) is ON the circles, knowing that it is IN the circle would be of no use.
so radius is √(1-(-3))^2 + (6-3)^2)
= √(16+9) = √25 = 5
area = π(5^2) = 25π square units
b(1,6) is ON the circles, knowing that it is IN the circle would be of no use.
so radius is √(1-(-3))^2 + (6-3)^2)
= √(16+9) = √25 = 5
area = π(5^2) = 25π square units
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