Asked by Aditya
A stream of water flowing horizontally with the speed of 15m/s gushes out of a tube of cross-sectional area 10-2m2 and hits a vertical wall nerby. What is the force exerted on the wall by the impact of water assuming it does not rebound?
Answers
Answered by
drwls
Force = rate of change of momentum
Show your work for further assistance
Show your work for further assistance
Answered by
Emily
We know that speed of water is 15m/s so we can assume the tube height to be 15 m. Are of cross section is given... So volume of the cylinder(water flowing) can be calculated
Volume=0 .15 m^3
Density=mass/ volume.as density of water is 1000 kg/m^3..... Mass of water is 150 kg.
Force=mv-mu
=150(15) -150(0)
2250 N
Volume=0 .15 m^3
Density=mass/ volume.as density of water is 1000 kg/m^3..... Mass of water is 150 kg.
Force=mv-mu
=150(15) -150(0)
2250 N
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.