Asked by Anonymous
jet stream which is flowing at a rate of 80 miles per hour. It travels with the jet stream for 5 hours and then reduces its altitude, flying out of the jet stream for 4 more hours. The plane, while out of the jet stream, covered 550 miles less than it did during the 5 hours it was in the jet stream. How fast was the plane flying out of the jet stream?
Answers
Answered by
Damon
distance in stream = (v+80)5
distance out of stream = 4 v
4 v + 550 = 5(v+80)
distance out of stream = 4 v
4 v + 550 = 5(v+80)
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