Asked by Cindy
Car A is moving at a constant speed of 10.0 m/s and passes Car B which is at rest. 10seconds after, the latter follows with an acceleration of 0.5 m/s^2. Determine the distance that the latter has to travel before it overtakes the former.
Answers
Answered by
Steve
at time t seconds after passing car B,
car A has gone 10t
car B has gone 1/2 a(t-10)^2 = .25(t-10)^2
the two distances are equal at time t=58.28
so, both have gone 582.8m
car A has gone 10t
car B has gone 1/2 a(t-10)^2 = .25(t-10)^2
the two distances are equal at time t=58.28
so, both have gone 582.8m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.