Question
a car moving with a constant accerleration of 2.2 mi/h/s covers the distance of two points in 6 s. Its velocity as it passes the second point at 45 mi/h. What was its velocity at the first point?
Answers
drwls
(Change in velocity)/6s = 2.2 mi/h/s
(45 - V1)6 = 2.2
45 - V1 = 13.2
V1 = 31.8 mph
(45 - V1)6 = 2.2
45 - V1 = 13.2
V1 = 31.8 mph