Asked by Lori
A certain mountain has an elevation of 19,583 feet. In 1907, the glacier on this peak covered 10 acres.By 2002, this glacier had melted to only 1 acre. (a) Assume this glacier melted at a constant rate each year. Find this yearly rate. (b)Use your answer from part (a)to write a linear equation that gives the acreage A of this glacier t years past 1907.
Answers
Answered by
Steve
a constant rate in acres/year, or a constant rate as a %age of the glacier's area?
In the first case, it was reduced by 9 acres in 95 years, or .0947 acres/yr
In the second case, it was reduced to 10% in 95 years, at a rate of 2.4%/yr
I guess you want .0947 acres/yr, since it's asking for a linear equation.
A = 10 - .0947x where x=years since 1907.
Extra credit: At that rate, when will the glacier be gone?
In the first case, it was reduced by 9 acres in 95 years, or .0947 acres/yr
In the second case, it was reduced to 10% in 95 years, at a rate of 2.4%/yr
I guess you want .0947 acres/yr, since it's asking for a linear equation.
A = 10 - .0947x where x=years since 1907.
Extra credit: At that rate, when will the glacier be gone?
Answered by
Lori
Yes, I want the .0947 so that I could do the linear equation. Since the linear equation is A=10-.947(95)which means A = 1.0035?
Answered by
Lori
I have to round the .0947 to the nearest thousandth so it would be .09?
Answered by
Ms. Sue
You rounded to the nearest hundredth.
Answered by
Lori
So then it is .095?
Answered by
Ms. Sue
Right. 0.095
Answered by
Lori
Thank you!