Asked by John Scott
An 80 kg man stands in an elevator. What force does the floor of the elevator exert on the man if
a) the elevator is stationary?
b) the elevator accelerates upward at 2 m/s2?
c) the elevator rises with constant velocity 4 m/s?
d) while rising, the elevator decelerates at 1.5 m/s2?
e) the elevator descends with constant velocity 7 m/s?
I'm completely confused. Can someone explain ?
a) the elevator is stationary?
b) the elevator accelerates upward at 2 m/s2?
c) the elevator rises with constant velocity 4 m/s?
d) while rising, the elevator decelerates at 1.5 m/s2?
e) the elevator descends with constant velocity 7 m/s?
I'm completely confused. Can someone explain ?
Answers
Answered by
Henry
a. F = M*g = 80 * 9.8 = 784 N.
b. F-784 = M*a.
F-784 = 80*2 = 160.
F = 944 N.
c. F-784 = M*a.
F-784 = M*0 = 0.
F = 784 N.
d. F-784 = M*a.
F-784 = 80*(-1.5).
F-784 = -120.
F = 664 N.
b. F-784 = M*a.
F-784 = 80*2 = 160.
F = 944 N.
c. F-784 = M*a.
F-784 = M*0 = 0.
F = 784 N.
d. F-784 = M*a.
F-784 = 80*(-1.5).
F-784 = -120.
F = 664 N.
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