Question
A 60.0 kg person rides in elevator while standing on a scale. The elevator has an acceleration 2.00 m/s^2 upward. What is the reading on the scale?
Answers
m=60.0
a=2.00
FN-mg=ma
FN=ma + mg
FN=m(a+g)
FN=60(2.00+9.8)
Answer 708N
a=2.00
FN-mg=ma
FN=ma + mg
FN=m(a+g)
FN=60(2.00+9.8)
Answer 708N
It's correct
If you need the scale reading in kg just divide the force by g
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