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A volume of 70.0mL of aqueous potassium hydroxide(KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What...Asked by Lindsey
A volume of 40.0 of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 20.2 of 1.50M H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)--->K2SO4(aq)+2H2O(l)
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Answered by
DrBob222
You need units on those volumes.
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