Question
A volume of 40.0 of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid h2so4. What was the molarity of the solution if 20.02 of 1.50M h2s04 was needed?
Who helps me to solve it for me.
Who helps me to solve it for me.
Answers
Technically the problem can't be solved because you have no units for 40.0 and 20.02. Assuming those are mL, the problem is solved as follows:
2KOH + H2SO4 ==> K2SO4 + 2H2O
mols H2SO4 = M x L = ?
mols KOH = 2x that (look at the equation coefficients)
Then M KOH = mols KOH/L KOH.
2KOH + H2SO4 ==> K2SO4 + 2H2O
mols H2SO4 = M x L = ?
mols KOH = 2x that (look at the equation coefficients)
Then M KOH = mols KOH/L KOH.