Asked by Lynn
verify the following identity:
tanx+cotx/cscx=secx
tanx+cotx/cscx=secx
Answers
Answered by
Reiny
looks like we have some "homework dumping" going on here.
I will do one more, and let you looks at my methods.
Then you tell me where you are having problems
Again, you must mean
(tanx + cotx)/cscx = secx
LS = (sinx/cosx + cosx/sinx)(sinx)
= (sin^2 x + cos^2 x)/(sinxcosx) (sinx)
= 1/cosx
= sec x
= RS
I will do one more, and let you looks at my methods.
Then you tell me where you are having problems
Again, you must mean
(tanx + cotx)/cscx = secx
LS = (sinx/cosx + cosx/sinx)(sinx)
= (sin^2 x + cos^2 x)/(sinxcosx) (sinx)
= 1/cosx
= sec x
= RS
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