Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
a man pushes a box of mass 5 kg in a horizontal direction by 10 N force on the surface through a distance of 5m if the cofficie...Asked by 1999999
a man pushes a box of mass 5 kg in a horizontal direction by 10 N force on the surface through a distance of 5m if the cofficien of kinetic friction is 0.2 the total work done on the box is
Answers
Answered by
ajayb
Work done by the man = F*d = 10*5 = 50 J
work done by frictional force = mu*mg*d
= - 0.2*5*9.8*5 = - 49 J
Net work done on the box = 50-49= 1 J
work done by frictional force = mu*mg*d
= - 0.2*5*9.8*5 = - 49 J
Net work done on the box = 50-49= 1 J
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.