Asked by sammeh
a person pushes a 10kg mass at a constant speed across a u=0.150, 8.50m long floor at a constant speed
how much work does the person do? (125J)
how much work does friction do? ( -125J)
how much work does the person do? (125J)
how much work does friction do? ( -125J)
Answers
Answered by
drwls
The friction force is M g u = 10*9.81*.15 = 14.7 N
Multiply Force x distance for work done. That would be 14.7 x 8.5 = 125 J
Friction has the work done on it, and is therefore equal and opposite
Multiply Force x distance for work done. That would be 14.7 x 8.5 = 125 J
Friction has the work done on it, and is therefore equal and opposite