work done by 500 n force = 500 N * 100 m = 50,000 Joules input
work done by friction = -0.2 * 10 * 9.81 * 100 m = -1962 Joules
net work = increase in kinetic energy = 48,038 Joules
A car with a mass of 10kg is pushed 100m parallel with the horizontal surface with a force of 500N. The surface has a coefficient of friction of 0.2. How much work does each of the following forces do on the box: (a) 500N push, (b) the friction force, (c) What is the net work done on the car?
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