Asked by Ande2
Two boys each of mass 10kg sit at a distance 1.5metres from a pivot of a seasaw. If another boy of mass 30kg sit at the distance 1.0metres from the pivot, would the seasaw balance horizontally?
Answers
Answered by
bobpursley
30(1)=2*10*1.5 ???
30=30
yes.
30=30
yes.
Answered by
Henry2
No, because the seesaw was already balanced. So, when the 3rd boy climbed on, it became unbalanced.
Balanced: F1*d1 = F2*d2.
;
Balanced: F1*d1 = F2*d2.
;
Answered by
Henry2
I assumed the 2 boys were on opposite sides of the pivot; because if they were on the same side, they occupied the same space at the same time which is impossible.
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