Question

a man pushes a box of mass 5 kg in a horizontal direction by 10 N force on the surface through a distance of 5m if the cofficien of kinetic friction is 0.2 the total work done on the box is

Answer 1

F=F(fr)=μmg
W=F(fr)•s= μmgs

Answer 2

Since
F=F(fr)=μmg,
the work is
W=F(fr)•s= μmgs