Ask a New Question

Question

A ball is released from a hot air balloon moving downward with a velocity of
-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.
13 years ago

Answers

bobpursley
hf=hi+vi*t+1/2 a t^2
0=1000-10t-4.9t^2

solve the quadratic

t=(-10+-sqrt(100+19600))/-9.8
t=-150/-9.8=15.3sec

check that.
13 years ago
lllll
incorrect
9 years ago

Related Questions

A 50 g ball is released from rest 1.0 m above the bottom of the track shown in the figure. It rolls... A bowling ball is released at the near right corner of a bowling lane and travels 19.1 m at an angle... if a ball is released from a certain height.The velocity-time graph which represents the motion of... If the ball is released from rest at a height of 0.64 m above the bottom of the track on the no-slip... a 0.20 kg ball is released from a height of 10 m above the beach; the impression the ball makes in t... A 48 g ball is released from rest at h = 1.4 m above the bottom of the track shown in the figure bel... a ball is released from the top of a 67.0 m high building. At the same instant a second ball is shot... A ball is released at a height of h=3.00 m on a frictionless 30.0 degree slope. At the bottom, it tu... The tennis ball was released from a shooting pot with the initial velocity of 30m/s at the angle o... A ball Is released at a height of 8 inches to roll inside a half-cylinder. It rolls to a height of 2...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use