Asked by Giovanni

A tennis ball is released at 30 degrees. It reaches max height of 20 ft find initial speed

Answers

Answered by bobpursley
So we are to assume its initial velocity was 30 deg above the horizon.
verticalspeed=vsin30

The KE in the horizontal direction remains constant, but in the vertical
1/2 m v'^2+mgh=1/2 m (V sin30)^2
at the top, v' is zero, so
g*20=1/2 V^2 *1/4)

v^2=8g*20ft=160ft*32ft/s^2

v=sqrt (160*32) ft/sec=21.6ft/s

check that.
Answered by Henry
Y^2 = Yo^2 + 2g*h = 0.
Yo^2 - 64*20 = 0, Yo = 35.8 Ft/s.

Vo*sin30 = 35.8, Vo = 71.6 Ft/s.
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