Asked by Anonymous
a 0.20 kg ball is released from a height of 10 m above the beach; the impression the ball makes in the sand is 5.0 cm deep while the ball stops uniformly. what is the force acting on the ball by the sand?
Answers
Answered by
bobpursley
Initial PE= final force*distance
.2*9.8*10=finalforce*.05
solve for force.
.2*9.8*10=finalforce*.05
solve for force.
Answered by
dan
392 N
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