Asked by Tifini
Suppose a parabola has its vertex at (0, 1) and its zeros at x = -3 and x = 3. Then equals _____.
A. 9-x^2
B. 1-1/9x^2
C. x^2-1
D. x^2-9
A. 9-x^2
B. 1-1/9x^2
C. x^2-1
D. x^2-9
Answers
Answered by
Steve
vertex at (0,1) means y = -ax^2 + 1 where a>0.
since y=0 when x=3, we have
y = -1/9 x^2 + 1
(B)
since y=0 when x=3, we have
y = -1/9 x^2 + 1
(B)
Answered by
Henry
B. Y = 1-(1/9)x^2 = 1 - x^2/9.
V(0,1).
When Xv = 0,
Y = 1-0/9 = 1.
When X = -3,
Y = 1 - (-3)^2 / 9 = 1--1 = o.
When X = 3,
Y = 1- 3^2 / 9 = 1 - 1 = 0.
Choice B satisfies all requirements.
Therefore,the answer is B.
V(0,1).
When Xv = 0,
Y = 1-0/9 = 1.
When X = -3,
Y = 1 - (-3)^2 / 9 = 1--1 = o.
When X = 3,
Y = 1- 3^2 / 9 = 1 - 1 = 0.
Choice B satisfies all requirements.
Therefore,the answer is B.