Consider a parabola P that is congruent (has the same shape) to y=x^2 , opens upward, and has vertex (2,-3). Now find the equation of a new parabola that results if P is Compressed to a factor of 1/2

Question

Translated 2 units to the left
Translated 3 units up
Reflected in the x-axis and translated 2 units to the right and 4 units down

Answer 1

vertex at (2,-3) y = (x-2)^2 - 3
if compressed vertically, then 2y = (x-2)^2-3
if compressed horizontally, y = (2x-2)^2-3