Asked by Cinderella
How would I put this parabola in standard form: x^2-6x+8y-31
Here how I started it:
x^2-6x+9=-8y+31
Im not sure what to do from here :(
Here how I started it:
x^2-6x+9=-8y+31
Im not sure what to do from here :(
Answers
Answered by
Anonymous
If x^2-6x+8y-31 mean:
x^2-6x+8y-31=0 then
8y= -x^2+6x+31 Divide with 8
y= -x^2/8 + 6x/8 + 31/8
y= -x^2/8 + 3x/4 + 31/8
x^2-6x+8y-31=0 then
8y= -x^2+6x+31 Divide with 8
y= -x^2/8 + 6x/8 + 31/8
y= -x^2/8 + 3x/4 + 31/8
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