Ask a New Question

Asked by Exist

Suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7, 1). Write the equation of the parabola in vertex form.

A y = -4(x - 5)^2 + 9
B y = -7(x +9)^2 - 5
C y = -0.06(x -5)^2+9
D y = -2(x+5)^2 + 9
2 years ago

Answers

Answered by Exist
I have no idea how to do this.
2 years ago
Answered by A Person
D y = -2(x + 5)^2 + 9 is your answer.
2 years ago

Related Questions

Suppose a parabola has its vertex at (0, 1) and its zeros at x = -3 and x = 3. Then equals _____.... Suppose a parabola f(x) has its vertex at (0, 25) and its zeros at x = -5 and x = 5. Then f(x)equals... a parabola whose axis is parallel to the y axis passess through the points {1,1), (2.2) and (-1,5).... Suppose a parabola has an axis of symmetry at x = -2, a minimum height at -6, and passes through the... Suppose a parabola has an axis of symmetry at x = −2, a maximum height of 7 and also passes through... Suppose a parabola has an axis of symmetry at x equals negative eight , a maximum height of 2, and p... Suppose a parabola has an axis of symmetry at `x=-2,` a maximum height of `8`, and passes through th...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use