Asked by Lynn
What is the minimal sample size needed for a 99% confidence interval to have a maximal margin of error of 0.06 if there is no preliminary estimate for p?
Answers
Answered by
MathGuru
Formula to find sample size:
n = [(z-value)^2 * p * q]/E^2
... where n = sample size, z-value is found using a z-table for 99% confidence (which is 2.58), p = .5 (when no value is stated in the problem), q = 1 - p, ^2 means squared, * means to multiply, and E = 0.06
Plug values into the formula and calculate n.
I hope this will help get you started.
n = [(z-value)^2 * p * q]/E^2
... where n = sample size, z-value is found using a z-table for 99% confidence (which is 2.58), p = .5 (when no value is stated in the problem), q = 1 - p, ^2 means squared, * means to multiply, and E = 0.06
Plug values into the formula and calculate n.
I hope this will help get you started.
Answered by
Rory
301
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