Question
Suppose x has a normal distribution with sigma = 1.2. Find the minimal sample size required so that for a 95% confidence interval, the maximal margin of error E = 0.5.
Answers
n = (z times sigma divided by E)^2
n = (1.96)(1.2)/.05 = 15.68 now square 245.8 or 246
n = (1.96)(1.2)/.05 = 15.68 now square 245.8 or 246
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