Asked by Brock
Complete the square to write the equation x^2 + y^2 - 6x - 2y + 4 = 0 in standard form. Use the standard form of the equation to identify the center and the radius of the circle.
Answers
Answered by
Reiny
x^2 + y^2 - 6x - 2y + 4 = 0
x^2 - 6x + <b> 9 </b> + y^2 - 2y + <b> 1 </b> = -4 + <b> 9 </b> + <b> 1 </b>
(x-3)^2 + (y-1)^2 = 6
I will leave it up to you to take it from there.
x^2 - 6x + <b> 9 </b> + y^2 - 2y + <b> 1 </b> = -4 + <b> 9 </b> + <b> 1 </b>
(x-3)^2 + (y-1)^2 = 6
I will leave it up to you to take it from there.
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