Asked by Albert

find dy/dx by implicit differentiation

a) xy + x^5y^2 + 3x^3 - 4 = 1

b) lny = cos x

thank you

Answers

Answered by Maya
dy/dx = (1y)+ (x)dy/dx + 5x^4y^2 + 2x^5y(dy/dx) + 9x^2
-y - 5x^4y^2 - 9x^2 = x(dy/dx) + 2x^5y (dydx)
(-y -5x^4y^2 -9x^2)/ (x + 2x^5y) = dy/dx
Answered by Albert
hi, is that all for a? please let me know, thank you Maya
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