Asked by cal

Find dy/dx by implicit differentiation given that

tan(4x+y)=4x
Answered by Steve
sec^2(4x+y) * (4+y') = 4
4+y' = 4cos^2(4x+4y)
y' = 4cos^2(4x+4y)-4 = -4sin^2(4x+4y)
Answered by cal
from the ans choices i choose:

dy/dx= - 4x^2/x^2+1

is that right
Answered by Steve
Looks good to me.
Answered by Sophia
sec^2(4x+y) * (4+y') = 4
4+y' = 4cos^2(4x+4)
y' = 4cos^2(4x+y)-4 = -4sin^2(4x+y)
Then sin^2(4x+y)=(4x/sqrt(16x^2+1))^2
=16x^2/(16x^2+1)
So y' = -4(16x^2/(16x^2+1))
=-64x^2/(16x^2+1))
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