Asked by drew
Nitrogen-13 has a half-life of 10 minutes. Given a starting mass of 2.00 g of nitrogen-13, how many grams will remain at the end of 30 minutes?
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
ln(No/N) = kt
No = 2.00
N = unknown
k from above
t = 30 min
Solve for N.
You can also use this.
30 min is obviously 3 half lives; therefore, 2<sup>3</sup> = 8 and 2.00 x (1/8) = ?
ln(No/N) = kt
No = 2.00
N = unknown
k from above
t = 30 min
Solve for N.
You can also use this.
30 min is obviously 3 half lives; therefore, 2<sup>3</sup> = 8 and 2.00 x (1/8) = ?
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