Asked by Samantha
The half-life of a certain radioactive element is about
1500 years. After
2800 years, what percentage P of a sample of this element remains?
1500 years. After
2800 years, what percentage P of a sample of this element remains?
Answers
Answered by
Steve
you have to multiply by 1/2 every 1500 years. So, the fraction remaining after t years is
(1/2)^(t/1500)
So, after 2800 years, the fraction remaining is
(1/2)^(2800/1500) = 2^-1.8667 = 0.2742 = 27.42%
Note that 2800 is almost 3000, or two half-lives. At t=3000, 1/2^2 = 1/4 = 0.25 will be left. So, we haven't quite reached that level yet.
(1/2)^(t/1500)
So, after 2800 years, the fraction remaining is
(1/2)^(2800/1500) = 2^-1.8667 = 0.2742 = 27.42%
Note that 2800 is almost 3000, or two half-lives. At t=3000, 1/2^2 = 1/4 = 0.25 will be left. So, we haven't quite reached that level yet.
Answered by
bobpursley
what is 100*e^(-.692*2800/1500) ?
Put this in your google search window:
100*e^(-.692*28/15)=
Put this in your google search window:
100*e^(-.692*28/15)=
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