Asked by Sara

The half-life for the second-order reaction of a substance A is 58.2 s when A0 = 0.63 mol L-1 Calculate the time needed for the concentration of A to decrease to the following values.

(a) one-third of its original value


(b) one-sixth of its original value


(c) one-seventh of its original value

Answers

Answered by DrBob222
What's wrong with substituting values into the second order equation and solving for time.
Could it be you don't know how to handle 1/3, 1/6, 1/7 th values?
If Ao = 0.63 then 1/3 that = ? for a; 1/6 that for b and 1/7 that for c.
Answered by Sara
I don't understand how to figure out K.

I used the information in the problem given to solve for k, and then plug that k in to solve for t, but it's not the correct answer.
Answered by DrBob222
t<sub>1/2</sub> = [1/k(Ao)]
Answered by Sara
I understand, but what is K or how can I determine K?
Answered by DrBob222
The problem GIVES you the half life. Use that and the equation I provided above to determine k.
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