If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time, give by g(t)= -16^2 + 64t. What is the maximum heigh reached by the ball?

Answer 1

max height is when g is max

I think you meant

g(t)=-16t^2+64t

g(t)=16t(4-t) or g=0 at t=0 and t=4

so max height is at t=2, the mid point

maxheight= -16*4+64*2=64meters