Asked by Anon
A swimmer launches himself upwards from a springboard 5.0 m above
the surface of the water in a swimming pool. His trajectory is (almost) vertical, and from the top of his trajectory he passes the springboard in just half of the time he takes to reach the water. How high above the springboard does he rise?
the surface of the water in a swimming pool. His trajectory is (almost) vertical, and from the top of his trajectory he passes the springboard in just half of the time he takes to reach the water. How high above the springboard does he rise?
Answers
Answered by
Scott
let h = height above board
h = (1/2) g (t/2)^2
h + 5 = (1/2) g t^2
h = (1/2) g (t/2)^2
h + 5 = (1/2) g t^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.