Asked by Bryce
If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time given y s(t) = -16t^2 + 64t. Graph this function for 0 < t<4, what is the maximum height?
Answers
Answered by
Henry
Tv = -B/2A = -64 / -32 = 2 s.
Y = -16*2^2 + 64*2 = 64 Ft, = Max. ht.
V(T,Y) = (2,64).
Complete the chart below for graphing.
(T,Y).
(0.5,28)
(1.0,48).
(1.5,
V(2.0,64).
(2.5,
(3.0,
(3.5,
Y = -16*2^2 + 64*2 = 64 Ft, = Max. ht.
V(T,Y) = (2,64).
Complete the chart below for graphing.
(T,Y).
(0.5,28)
(1.0,48).
(1.5,
V(2.0,64).
(2.5,
(3.0,
(3.5,
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