Asked by alsa
                Is Integral of f(x) w.r.t.x from 0 to a;equal to Integral of f(x-a) w.r.t.x from 0 to a?
            
            
        Answers
                    Answered by
            MathMate
            
    To show the results, we assume
F(x)=∫f(x)dx
then
∫f(x)dx from 0 to a is F(a)-F(0)
and
∫f(x-a)dx from 0 to a is F(0)-F(0-a)
=F(0)-F(-a)
=-F(-a)+F(0)
For the two to be equal, we require:
F(a)-F(0) = -F(-a) + F(0)
or
F(a)-F(-a) = 2F(0)
Which is not generally true. So the answer is no. A counter example is when f(x)=sin(x).
However, equality can be satisfied if F(x) is an odd function where F(0)=0 (such as sin(x)). This means that equality will hold if f(x)=±k*cos(x).
    
F(x)=∫f(x)dx
then
∫f(x)dx from 0 to a is F(a)-F(0)
and
∫f(x-a)dx from 0 to a is F(0)-F(0-a)
=F(0)-F(-a)
=-F(-a)+F(0)
For the two to be equal, we require:
F(a)-F(0) = -F(-a) + F(0)
or
F(a)-F(-a) = 2F(0)
Which is not generally true. So the answer is no. A counter example is when f(x)=sin(x).
However, equality can be satisfied if F(x) is an odd function where F(0)=0 (such as sin(x)). This means that equality will hold if f(x)=±k*cos(x).
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.