what is the integral of ( x^2 / (x+1)dx

Answer 1

x^2/(x+1) dx
| = integration symbol

|x^2/(x + 1) dx
Using long divsion
|x - 1 + 1/(x + 1) dx
|x dx - |1 dx + |1/(x + 1) dx

1/2 x^2 - x + ln |x + 1| + C