Asked by John Q
Integral of (ln^6x)/x dx
Answers
Answered by
MathMate
Try substitution of u=lnx,
du = dx/x
dx=xdu
∫ln^6(x)dx/x
=∫ln^6(x)dx/x
=∫u^6*xdu/x
=∫u^6du
=u^7/7+C
=ln^7(x)/7 + C
du = dx/x
dx=xdu
∫ln^6(x)dx/x
=∫ln^6(x)dx/x
=∫u^6*xdu/x
=∫u^6du
=u^7/7+C
=ln^7(x)/7 + C
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