Asked by Katie
What is the area of a regular pentagon with a side length of 10 inches and a distance from the center to a vertex of 10 inches?
Round your answer to the nearest tenth.
Round your answer to the nearest tenth.
Answers
Answered by
Reiny
Look at one of the five isosceles triangle
each has a 72 degree angle with sides of 10 containing that angle.
Use the cosine law to find the base of that triangle
x^2 = 10^2 + 10^2 - 2(10)(10)cos 72
x = ...
Once you have that, find the area of the triangle (1/2)(10)(10sin(above angle)
then multiply by 5
each has a 72 degree angle with sides of 10 containing that angle.
Use the cosine law to find the base of that triangle
x^2 = 10^2 + 10^2 - 2(10)(10)cos 72
x = ...
Once you have that, find the area of the triangle (1/2)(10)(10sin(above angle)
then multiply by 5
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