Asked by Sara
what is the area of a regular hexagon inscribed in a circle with area of 9?
Answers
Answered by
Henry
Ac = pi*r^2 = 9
r^2 = 9/pi = 2.86
r = 1.69.
Ah = 2.60 * r^2
Ah = 2.60 * (1.69)^2 = 7.43 Sq. Units. =
Area of hex.
r^2 = 9/pi = 2.86
r = 1.69.
Ah = 2.60 * r^2
Ah = 2.60 * (1.69)^2 = 7.43 Sq. Units. =
Area of hex.
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