v=sqrt(2as) =sqrt(2•2.5•2)=3.16 m/s,
H=gt²/2 => t =sqrt(2H/g) =
=sqrt(2•1.5/9.8) =0.55 s.
X =v•t =3.16•0.55 = 1.75 m.
A box of mass m = 0.20 kg slides across frictionless tabletop from rest, with 2.5 m/s2 acceleration.
The length of the tabletop is L = 2.00 m and its height is H = 1.50 m. The box then slides off the edge and hits the floor at some distance away, Find the distance x.
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