Asked by Madison

you slide down a pole at a mass of 80kg with an acceleration of 4m/s^2, How do you show that the friction force that acts on you is 480N?
Answered by Damon
Force = mass *acceleration
Force down = 80*9.8 = 784 N
force down - Ffriction = 80 (4)
solve for Ffriction
Answered by drwls
Weight - Friction force = M a

Friction force = Ma - Mg
= 5.8 m/s^2 * M

They apparently want you to use 10 m/s^2 for g, although the correct value is 9.8 m/s^2.
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