Asked by Cyrus
A uniform solid cylinder of mass M = 6 kg is rolling without slipping along a horizontal surface. The velocity of its center of mass is 27.6 m/s. Calculate its energy
Answers
Answered by
Elena
KE = KE (translational) + KE (rotational)=
=m•v²/2 + Iω²/2 =
= m•v²/2 +0.5 (m•R²/2)(v²/R²) =
=0.75 • m•v².
=m•v²/2 + Iω²/2 =
= m•v²/2 +0.5 (m•R²/2)(v²/R²) =
=0.75 • m•v².