Asked by ali
A uniform solid cylinder of mass 1kg roll with out slipping on aflat surface at aspeed of 4m/s. What is the total kinetic energy of the cylinder?
Answers
Answered by
Damon
v = omega r so omega = v/r
I =(1/2) m r^2
(1/2) m v^2 + (1/2) I omega^2
=(1/2) m v^2 + (1/2)m r^2 (v^2/r^2)
= m v^2
half the energy is linear and half is rotational ;)
I =(1/2) m r^2
(1/2) m v^2 + (1/2) I omega^2
=(1/2) m v^2 + (1/2)m r^2 (v^2/r^2)
= m v^2
half the energy is linear and half is rotational ;)