Question

1. A 500.0 g metal block absorbs 1.125 × 104 J of heat to raise its temperature by 50.0 K. What is the substance?

Answer 1

The heat capacity per atom in a solid near room temperature is 3 k with k the Boltzmann constant. If you compute the heat capacity of the 500.0 g metal block, and divide that by 3 k, you get the number of atoms in tha block.

If you then divide the mass of 0.5000 kg by the number of atoms, you get the atomic mass.

Answer 2

Q=m•c•ΔT
c= Q/ m• ΔT = 1.125•10^4/0.5•50 =450 J/kg•K
This is specific heat of iron